Elimination

The base removes a hydrogen from the carbon next to bromine. The C-H electrons form the C=C pi bond as bromide departs, so elimination removes H and Br without changing the two-carbon skeleton.

Reagents
KOH in ethanol
Conditions
Heat with ethanolic alkali
Reaction class
Elimination
Equation
CH3CH2Br + KOH -> CH2=CH2 + KBr + H2O

Overview

The base removes a hydrogen from the carbon next to bromine. The C-H electrons form the C=C pi bond as bromide departs, so elimination removes H and Br without changing the two-carbon skeleton.

Transformation

Bromoethane → Ethene

Equation
CH3CH2Br + KOH -> CH2=CH2 + KBr + H2O
Reactants
Bromoethane + Potassium hydroxide
Products
Ethene + Potassium bromide + Water
Reagents
KOH in ethanol
Environment
Heat with ethanolic alkali
Reaction class
Elimination
Mechanism
E2 elimination
Evidence level
source-backed molecular example

Scope and limitations

Scope
A beta hydrogen is removed as bromide leaves.
Limitations
Substitution competes, especially for a primary substrate; the equation gives the intended elimination branch.

Related reactions

References

  1. Pearson Edexcel International Advanced Level Chemistry Scheme of WorkPearson Education Limited · Pearson qualifications · 2018

    Official Pearson teaching guidance specifying chloroalkane-relevant conditions: aqueous alkali, ethanolic potassium hydroxide, alcoholic ammonia, alcoholic potassium cyanide, and PCl5 alcohol chlorination.